Get the permission name more elegent

This commit is contained in:
Josué Tille 2019-05-10 22:22:57 +02:00
parent d0f422ee39
commit fd76f5544a
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@ -71,11 +71,10 @@ def user_permission_list(auth, app=None, permission=None, username=None, group=N
'(objectclass=permissionYnh)', permission_attrs)
for res in result:
permission_name = res['cn'][0].split('.')[0]
try:
app_name = res['cn'][0].split('.')[1]
permission_name, app_name = res['cn'][0].split('.')
except:
logger.warning(m18n.n('permission_name_not_valid', permission=per))
logger.warning(m18n.n('permission_name_not_valid', permission=res['cn'][0]))
group_name = []
if 'groupPermission' in res:
for g in res['groupPermission']: